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codeforces round265 div1 D World of Darkraft - 2

ShinriiTin posted @ 2015年6月12日 16:33 in 未分类 with tags dp 概率与期望 , 600 阅读

详见zhj的15年集训队论文

Portal

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;

#define rep(i,a,b) for(int i=a;i<b;++i)
typedef long double ld; 

const int MAXN=1000; 

int n,k,cur;

ld dp[2][MAXN];

int main(){
	scanf("%d%d",&n,&k);
	for(int i=n;i;--i){
		cur^=1;
		int B=701;
		rep(j,1,B){
			dp[cur][j]=(dp[cur^1][j]+(1.+j)/2)*j;
			dp[cur][j]+=(dp[cur^1][j+1]+j);
			dp[cur][j]/=j+1;
			dp[cur][j]+=dp[cur^1][j]*(k-1);
			dp[cur][j]/=k;
		}
	}
	ld ans=dp[cur][1]*k;
	printf("%.20f\n",(double)ans);
	return 0;
}
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Brooke De 说:
2018年11月28日 16:00

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